1.2. Subspaces
Definition 1.2.1. A subset \(W\) of a vector space \(V\) over a field \(F\) is called a subspace of \(V\) if \(W\) is a vector space over \(F\) with the operations of addition and scalar multiplication defined on \(V.\)
Remark 1.2.2. Let \(V\) be a vector space over \(F,\) and \(W\) a subset of \(V.\) Because (VS1), (VS2), (VS5), (VS6), (VS7), and (VS8) hold for all vectors in \(V,\) these automatically hold for the vectors in \(W.\) Thus \(W\) is a subspace of \(V\) if and only if the following four properties are true in \(W.\)
- \(\forall u,v\in W \ (u+v\in W).\)
- \(\forall c \in F\ \forall u\in W \ (cu\in W).\)
- \(\exists u\in W \ \forall v\in W \ (v+u=v).\)
- \(\forall u\in W \ (-u\in W).\)
Theorem 1.2.3. Let \(V\) be a vector space over \(F,\) and \(W\) a subset of \(V.\) Then \(W\) is a subspace of \(V\) if and only if the following three properties are true in \(W.\)
- \(0_V\in W.\)
- \(\forall u,v\in W \ (u+v\in W).\)
- \(\forall c \in F\ \forall u\in W \ (cu\in W).\)
Proof. Suppose that \(W\) is a subspace of \(V.\) By Definition 1.2.1, (2) and (3) hold, and there exists \(u\in W\) such that \(\forall v\in W \ (v+u=v).\) But in \(V,\) we have \(v+0_V= v,\) and thus, by Theorem 1.1.8, \(u=0_V.\) Therefore (1) holds. Conversely, suppose that (1), (2), and (3) hold. Then \((-1)u\in W.\) We also have \(0u=0_V,\) because \(u+0u=1u+0u=(1+0)u=1u=u.\) Thus \(u+(-1)u=1u+(-1)u=(1+(-1))u=0u=0_V.\) Therefore \(-u=(-1)u\in W.\) From Remark 1.2.2, we can see that \(W\) is a subspace of \(V.\) \(\square\)
Example 1.2.4. The transpose \(A^{{\!\top}}\) of an \(m\times n\) matrix \(A\) is the \(n\times m\) matrix defined by \((A^{\!\top})_{ij}=A_{ji}.\) A symmetric matrix is a matrix \(A\) such that \(A^{\!\top}=A.\) It is clear that a symmetric matrix must be square. It is because that \(A\) is a \(m\times n\) matrix with \(m<n\) implies that there are no entries in \(A^{\!\top}\) corresponding to the entries \(A_{in}.\) The set \(W\) of all symmetric matrix in \({F}^{n\times n}\) is a subspace of \({F}^{n\times n}\) since Theorem 1.2.3 hold: Since \(O^{\!\top}=O,\) \(O\in W.\) Let \(A,B\in W.\) We have \(A_{ij}=A_{ji}\) and \(B_{ij}=B_{ji},\) thus \((A+B)_{ij}=A_{ij}+B_{ij}=A_{ji}+B_{ji}=(A+B)_{ji}.\) Therefore \((A+B)\in W.\) Let \(A\in W\) and \(c\in F.\) We have \(A_{ij}=A_{ji},\) thus \((cA)_{ij}=cA_{ij}=cA_{ji}=(cA)_{ij}.\) Therefore \(cA\in W.\)
Example 1.2.5. Let \(n\) be a nonnegative integer, and let \({F}_n[x]\) consist of all polynomials in \({F}[x]\) having degree less than or equal to \(n.\) Since the zero polynomial \(\mathbf 0\in {F}[x]\) has degree \(-\infty,\) it is in \({F}_n[x].\) Let \(P, Q \in {F}[x].\) Since \(\text{deg}(P+Q)\leq \max{\lbrace \text{deg}(P),\text{deg}(Q)\rbrace }\leq n,\ (P+Q)\in {F}_n[x].\) Let \(P \in {F}[x].\) Since \(\text{deg}(cP)=\text{deg}(P)\leq n, \ cP\in {F}_n[x].\) It therefore follows from Theorem 1.2.3 that \({F}_n[x]\) is a subspace of \({F}[x].\)
Example 1.2.6. Let \(C(\mathbb R, \mathbb R)\) denote the set of all continuous real-valued functions defined on \(\mathbb R.\) Since constant functions are continuous functions, \(\mathbf {0} \in C(\mathbb R, \mathbb R).\) Let \(f,g\in C(\mathbb R, \mathbb R).\) Since \(f+g\) is continuous function, \((f+g)\in C(\mathbb R, \mathbb R).\) Let \(f\in C(\mathbb R, \mathbb R)\) and \(c\in \mathbb R.\) Since \(cf\) is a continuous function, \(cf\in C(\mathbb R, \mathbb R).\) It therefore follows from Theorem 1.2.3 that \(C(\mathbb R, \mathbb R)\) is a subspace of \({F}[x].\)
Example 1.2.7. An \(n\times n\) matrix \(M\) is called diagonal matrix if \(M_{ij}=0\) whenever \(i\neq j,\) that is, if all its non-diagonal entries are zero. Let \(W\) denote the set of all \(n\times n\) diagonal matrices. Since \(O_{ij}=0\) for all \(i\) and \(j,\ O\in W.\) Let \(A,B\in W.\) If \(i\neq j\) then \((A+B)_{ij}=A_{ij}+B_{ij}=0+0=0.\) Thus \((A+B)\in W.\) Let \(A\in W\) and \(c\in F.\) If \(i\neq j\) then \((cA)_{ij}=cA_{ij}=c0=0c=0.\) Thus \(cA\in W.\) It therefore follows from Theorem 1.2.3 that \(W\) is a subspace of \({F}^{n\times n}.\)
Theorem 1.2.8. Let \(V\) be a vector space over a field \(F\). Then any intersection of subspaces of \(V\) is a subspace of \(V.\)
Proof. Let \(\mathcal C\) be a set whose elements are subspaces of \(V,\) and let \(W\) denote the intersection of \(\mathcal C.\) Since every subspace contains the zero vector, \(0_V\in W.\) Let \(a\in F\) and \(u,v\in W.\) Then \(u\) and \(v\) are elements of each subspace in \(\mathcal C.\) Since each subspace in \(\mathcal C\) is closed under the addition and scalar multiplication, \(u+v\) and \(cu\) are elements of each subspace in \(\mathcal C.\) Hence \(u+v\) and \(cu\) are also elements of \(W,\) so that \(W\) is a subspace of \(V\) by Theorem 1.2.3.\(\square\)
Exercises
Exercise 1. Prove that
\[(aA+bB)^{\!\top} = aA^{\!\top} + bB^{\!\top}\]for any \(A,B\in F^{m\times n}\) and any \(a,b\in F.\)
Proof. Let \(1\leq i \leq m\) and \(1\leq j \leq n.\) Then we have
\[\begin{aligned} \left( (aA+bB)^{\!\top}\right)_{ij} &= (aA+bB)_{ji}\\ &= (aA)_{ji} + (bB)_{ji}\\ &= aA_{ji} + bB_{ji}\\ &= a\left( A^{\!\top}\right)_{ij} + b\left( B^{\!\top}\right)_{ij}\\ &= \left( aA^{\!\top}\right)_{ij} + \left( bB^{\!\top}\right)_{ij}\\ &= \left( aA^{\!\top} + bB^{\!\top}\right)_{ij}. \end{aligned}\]Therefore \((aA+bB)^{\!\top} = aA^{\!\top} + bB^{\!\top}.\)\(\square\)
Exercise 2. Prove that \(A+A^{\!\top}\) is symmetric for any square matrix \(A.\)
References
- Friedberg, S. H., Insel, A. J., & Spence, L. E. (2025). Linear algebra (5th ed.). Pearson Education South Asia Pte Ltd.